Question

A ) 5x ao quadrado -10x +5 = 0

B ) 7x ao quadrado +13x -2 = 0

C ) x ao quadrado -7x +10 =0

ME AJUDEM!

Answer 1

Delta e bhaskara

A) $5x^{2}-10x+5=0$
Δ= b²-4.a.c
Δ= (-10)²-4.5.5
Δ= 100-100
Δ= 0

Bh = $\frac{-b +- \sqrt{delta}}{2.a}$
Bh = $\frac{-(-10) +- \sqrt{0}}{2.5}$
Bh = $\frac{10+-0}{10}$

x'=10+0/10 = 1
x''=10-0/10 = 1

B) $7x^{2}+13x-2=0$
Δ= b²-4.a.c
Δ= (13)²-4.7.(-2)
Δ= 169+56
Δ= 225

Bh = $\frac{-b +- \sqrt{delta}}{2.a}$
Bh = $\frac{-13 +- \sqrt{225}}{2.7}$
Bh = $\frac{-13 +- 15}{14}$

x'=-13+15/14 = 2/14 ou 1/7
x''=-13-15/14 = -28/14 = -2

C) $x^{2} -7x+10=0$
Δ= b²-4.a.c
Δ= (-7)²-4.1.10
Δ= 49-40
Δ= 9

Bh = $\frac{-b +- \sqrt{delta}}{2.a}$
Bh = $\frac{-(-7) +- \sqrt{9}}{2.1}$
Bh = $\frac{7 +- 3}{2}$

x'=7+3/2 = 5
x''=7-3/2 = 2