Question

A )
(5/7)^x2 =(49/25)^-x

B) √3^x-1 = (5√9^x)^2
preciso das respostas rapido por favor

Answer 1

Oi 

a)

(5/7)^x² = (49/25)^-x

(5/7)^x² = (5/7)^2x

x² = 2x

x² - 2x = 0

x*(x - 2) = 0

x1 = 0
x2 = 2

b) 

√3^x-1 = (5√9^x)^2

x =  (-log(3) - 4log(5))/(3log(3))

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