Física, perguntado por katicilene72, 6 meses atrás

a. 48 567 + 3 896 + 325 =

b. 54 672 − 8 798 =

c. 45 843 × 96 =

d. 2 976 × 58 × 34 =

e. 6 278 ÷ 73 =​

Soluções para a tarefa

Respondido por osextordq
1

a)

\frac{\begin{matrix}\space\space&\textbf{1}&1&1&1&\space\space\\ \space\space&\textbf{4}&8&5&6&7\\ \space\space&\textbf{0}&3&8&9&6\\ +&\textbf{0}&0&3&2&5\end{matrix}}{\begin{matrix}\space\space&\textbf{5}&2&7&8&8\end{matrix}}\\\\=52788

b)

\frac{\begin{matrix}\space\space&\textbf{4}&13&15&16&12\\ \space\space&\textbf{\linethrough{5}}&\linethrough{14}&\linethrough{16}&\linethrough{17}&\linethrough{2}\\ -&\textbf{0}&8&7&9&8\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&5&8&7&4\end{matrix}}\\\\=45874

c)

\frac{\begin{matrix}\space\space&\space\space&4&5&8&4&3\\ \space\space&\times \:&\space\space&\space\space&\space\space&9&6\end{matrix}}{\begin{matrix}0&2&7&5&0&5&8\\ 4&1&2&5&8&7&0\end{matrix}}\\\\\frac{\begin{matrix}\space\space&\textbf{\space\space}&1&1&\space\space&1&\space\space&\space\space\\ \space\space&\textbf{0}&2&7&5&0&5&8\\ +&\textbf{4}&1&2&5&8&7&0\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&4&0&0&9&2&8\end{matrix}}\\\\=4400928

d)

multiplique\\2976\times \:58\times \:34\\\\=5868672 < "calculadora"

e)

\frac{6278}{73}\\\\=86

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