Question

a/4=b/3=c/5=d/2, sabendo-se que 2a+b+3c+d=56. Determine os valores de a, b, c e d

Answer 1

Resposta:

${a\over4}={b\over3}={c\over5}={d\over2}\\ \\ 2a+b+3c+d=56$

Aplicando a regra da proporção

${2a+b+3c+d\over2(4)+3+3.(5)+2}=\\ \\ {2a+b+3c+d\over8+3+15+2}={56\over28}=2\\ \\ {a\over4}=2~~~~~~~{b\over3}=2~~~~~~~~~{c\over5}=2~~~~~~~~~{d\over2}=2\\ \\ \fbox{ a=8 }~~~~~\fbox{ b=6 }~~~~~~\fbox{ c=10 }~~~~~\fbox{ d=4 }$