Matemática, perguntado por brunadrumal, 6 meses atrás

a). (3z+y)^2
b). (2h^2 C^3)^2
c). (h^4 + C)^2
d) (3h^2 + z^2)​

Soluções para a tarefa

Respondido por Usuário anônimo
0

Resposta:

(3z+y)^2\\\\=\left(3z\right)^2+2\cdot \:3zy+y^2\\\\=9z^2+6zy+y^2\\\\\\\\(2h^2 c^3)^2\\\\=2^2\left(h^2\right)^2\left(c^3\right)^2\\\\=4\left(h^2\right)^2\left(c^3\right)^2\\\\=4h^4\left(c^3\right)^2\\\\=4h^4c^6\\\\\\\\(h^4+c)^2\\\\=\left(h^4\right)^2+2h^4c+c^2\\\\=h^8+2ch^4+c^2\\\\\\\\(3h^2 + z^2)\\\\0

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