Matemática, perguntado por srayzaa, 1 ano atrás


a)(3x+1)²+(x-2)(x+1)=-1
b)2x²-3x/2 + 1/4=0

Soluções para a tarefa

Respondido por juancordova1
2
a) (3x+1)^2+(x-2)(x+1)=-1》3x^2+2(3x)(2)+(1)^2=- 1》3x^2+6x+1+x^2+x-2x-2=-1》3x^2+6x+1+x^2-x-2=-1》3x^2+6x+1+x^2-2+1》4x^2+6x+1-1=0》4x^2+6x=0》x(4x+6)=0》x1=0 , 4x2-6=0》x1=0 , 4x2=-6》x1=0 , x2=-6/4(÷2)》x1=0 , x2=-3/2.......................... b)2x^2+3x/2+1/4=0》2x^2-3x+1=2+4》2x^2-3x+1=6》2x^2-3x+1-6=0》2x^2-3x-5=0》a=2,b=3,c=-5》x=3+,-\/3^2-4(2)(-5)/2(2)》x=3+,-\/9-8(-5)/4》x=3+,-\/9+40/4》x=3+,-\/49/4》x=3+,-\/49/4》x=3+,-7/4》x1=3+7/4》x1=10/4(÷2)》x1=5/2》x2=3-7/4》x2=-4/4》x2=-1
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