Question

A) 35 °F em °C 

B) 100 °C em °F 

Answer 1

$A) \\ \\ \frac{C}{5} = \frac{F-32}{9} \\ \\ \frac{C}{5} = \frac{35-32}{9} \\ \\ C= 5.\frac{1}{3} \\ \\ C\approxeq 1,6 \\ \\ \\B) \\ \\ \frac{C}{5} = \frac{F-32}{9} \\ \\ \frac{100}{5} = \frac{35-32}{9} \\ \\ 20.9=F-32 \\ \\ 180+32=F \\ \\ F=212$