Question

a) 312F→K+C
b) 1/4 de 1200°C k F
c) 773k °c F
alguém me ajuda a resolver essas questões por favor!​

Answer 1

Resposta:

Sejam as equivalências das escalas termométricas °C, K e °F dada por:

$\frac{T_{C}}{5} =\frac{T_{F}-32}{9} =\frac{T_{K}-273}{5}$

a) $\frac{T_{C}}{5} =\frac{312-32}{9} =\frac{T_{K}-273}{5}$

$\frac{T_{C}}{5} =\frac{312-32}{9}\ ; T_{C} =\frac{(5).280}{9} = 155,55\°C$

$\frac{312-32}{9} =\frac{T_{K}-273}{5}\ ; T_{K}=155,55+273 =428,55\ K$

b) (1/4) . 1200 = 300 °C

$\frac{300}{5} =\frac{T_{F}-32}{9} =\frac{T_{K}-273}{5}$

$\frac{300}{5} =\frac{T_{F}-32}{9}\ ; T_{F}=540+32 = 572\°F$

$\frac{300}{5} =\frac{T_{K}-273}{5}\ ;T_{K}=300+273=573\ K$

c) $\frac{T_{C}}{5} =\frac{T_{F}-32}{9} =\frac{773-273}{5}$

$\frac{T_{C}}{5} =\frac{773-273}{5}\ ; T_{C}=500\°C$

$\frac{T_{F}-32}{9} =\frac{773-273}{5}$

$T_{F} =900+32=932\°F$