Question

a) 3(x-5)(x+4)(x-2)=0
R:

b) (x+2)(x-2)=0
R:

c) (2x-1)(3x+2)=0

Answer 1

a)

3(x-5)(x+4)(x-2)=0

3×-15-3×+12-3×+6

3×-3×-3×=-15+12+6

3×=3

×=3÷3

×=1

b)

(x+2)(x-2)=0

2×-2×+2×-4

0+2×-4

2×=4

×=4÷2

×=2

c)

(2x-1)(3x+2)=0

6×+4×-3×-2

10×-3×-2

7×=2

×=7÷2

×=3,5

Espero ter ajudado