Question

a)3.x+2.(x+1)+x²=

b)3.(x+y+z)-3.x-3.y-3.z=

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Answer 1

Resposta:

a)3.x+2.(x+1)+x²=

$3x + 2x + 2 + {x}^{2} \\ {x}^{2} + 5x + 2$

b)3.(x+y+z)-3.x-3.y-3.z=

$3x + 3y + 3z - 3x - 3y - 3z \\ = 0$