Matemática, perguntado por AnaClara271081, 11 meses atrás

A-(3/5) elevado a 2 potencia
B-(1/4) elevado a 2 potencia
C-(3/7) elevado a 2 potencia
D-(1/10) elevado a 2 potencia
E-(4/9) elevado a 2 potencia
F-(12/7) elevado a 2 potencia
G-(1/5) elevado a 2 potencia
H-(3/11) elevado a 2 potencia
I- (5/13) elevado a 2 potencia
J-(8/3) elevado a 2 potencia
K-(10/13) elevado a 2 potencia
L-(4/3) elevado a 2 potencia
M-(2/3) elevado a 3 potencia
N-(1/4) elevado a 4 potencia
O-(2/5) elevado a 4 potencia
P-(3/5) elevado a 3 potencia
Q-(1/2) elevado a 3 potencia
R-(1/6) elevado a 3 potencia
S-(2/7) elevado a 2 potencia
T-(7/5) elevado a 2 potencia
U-(5/2) elevado a 0 potencia


IagoEstudante6ano: Não entedi o que tem que fazer

Soluções para a tarefa

Respondido por Usuário anônimo
5

Explicação passo-a-passo:

a) \sf \left(\dfrac{3}{5}\right)^2=\dfrac{3^2}{5^2}=\dfrac{9}{25}

b) \sf \left(\dfrac{1}{4}\right)^2=\dfrac{1^2}{4^2}=\dfrac{1}{16}

c) \sf \left(\dfrac{3}{7}\right)^2=\dfrac{3^2}{7^2}=\dfrac{9}{49}

d) \sf \left(\dfrac{1}{10}\right)^2=\dfrac{1^2}{10^2}=\dfrac{1}{100}

e) \sf \left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}

f) \sf \left(\dfrac{12}{7}\right)^2=\dfrac{12^2}{7^2}=\dfrac{144}{49}

g) \sf \left(\dfrac{1}{5}\right)^2=\dfrac{1^2}{5^2}=\dfrac{1}{25}

h) \sf \left(\dfrac{3}{11}\right)^2=\dfrac{3^2}{11^2}=\dfrac{9}{121}

i) \sf \left(\dfrac{5}{13}\right)^2=\dfrac{5^2}{13^2}=\dfrac{25}{169}

j) \sf \left(\dfrac{8}{3}\right)^2=\dfrac{8^2}{3^2}=\dfrac{64}{9}

k) \sf \left(\dfrac{10}{13}\right)^2=\dfrac{10^2}{13^2}=\dfrac{100}{169}

l) \sf \left(\dfrac{4}{3}\right)^2=\dfrac{4^2}{3^2}=\dfrac{16}{9}

m) \sf \left(\dfrac{2}{3}\right)^3=\dfrac{2^3}{3^3}=\dfrac{8}{27}

n) \sf \left(\dfrac{1}{4}\right)^4=\dfrac{1^4}{4^4}=\dfrac{1}{256}

o) \sf \left(\dfrac{2}{5}\right)^4=\dfrac{2^4}{5^4}=\dfrac{16}{625}

p) \sf \left(\dfrac{3}{5}\right)^3=\dfrac{3^3}{5^3}=\dfrac{27}{125}

q) \sf \left(\dfrac{1}{2}\right)^3=\dfrac{1^3}{2^3}=\dfrac{1}{8}

r) \sf \left(\dfrac{1}{6}\right)^3=\dfrac{1^3}{6^3}=\dfrac{1}{216}

s) \sf \left(\dfrac{2}{7}\right)^2=\dfrac{2^2}{7^2}=\dfrac{4}{49}

t) \sf \left(\dfrac{7}{5}\right)^2=\dfrac{7^2}{5^2}=\dfrac{49}{25}

u) \sf \left(\dfrac{5}{2}\right)^0=1

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