Matemática, perguntado por julianahello, 10 meses atrás

a) 3/5 + 1/3 × 2/5=
b) 7/3 + 2/3 - 1/4 =
C) 6/5 + 3/4 × 5/2 + 1/5 =
d) 3/4 × 1/5 - 2/20 + 3/10=
e) 5/3 + (1/4)²- (2/3)²=
f) (1/5)²- (1/10)²=


julianahello: certo , muito obrigado vai me ajudar muito mesmo !

Soluções para a tarefa

Respondido por Usuário anônimo
1

Resposta:

Explicação passo-a-passo:

A)

= 3/5 + 1/3 × 2/5

= 3/5 + 2/15

= (3.3 + 1.2)/15

= (9+2)/15

= 11/15

R.: 11/15

________________

b)

= 7/3 + 2/3 - 1/4

= 9/3 - 1/4

= 3 - 1/4

= (4.3 - 1)/4

= (12-1)/4

= 11/4

R.: 11/4

____________

C)

= 6/5 + 3/4 × 5/2 + 1/5

= 6/5 + 15/8 + 1/5

= 6/5 + 1/5 + 15/8

= 7/5 + 15/8

Mmc (5,8)= 40

= (8.7 + 5.15)/40

= (56+75)/40

= 131/40

R.: 131/40

----------------------------

5,8: 2

5,4: 2

5,2: 2

5,1: 5

1,1

= 2.2.2.5

= 8.5

= 40

______________________

d)

= 3/4 × 1/5 - 2/20 + 3/10

= 3/20 - 2/20 + 3/10

= 1/20 + 3/10

= (1+ 2.3)/20

= (1+6)/20

= 7/20

R.: 7/20

__________________

e)

= 5/3 + (1/4)²- (2/3)²

= 5/3 + 1/16 - (4/9)

= 5/3 + 1/16 - 4/9

= (48.5 + 9.1 - 16.4)/144

= (240 + 9 - 64)/144

= (249 - 64)/144

= 185/144

R.: 185/144

________________

Mmc = 144

3,16,9: 2

3, 8, 9: 2

3, 4, 9: 2

3,2,9: 2

3, 1, 9: 3

1,1, 3: 3

1, 1, 1

= 2.2.2.2.3.3

= 4.4.9

= 4.36

= 144

__________________

f)

= (1/5)²- (1/10)²

= 1/25 - 1/100

= (4 - 1)/100

= 3/100

R.: 3/100

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