Question

a) 3+√49-2³=

b) (12+3²×2)÷10

c) [(3²-2³)×6²-(4²+√121)]×2

d)1+{[2+√256×10²÷(3-15⁰)]×4}

Por favor me ajudem!​

Answer 1

a) 3 + V49 - 2³.

3 + 7 - 8 = 2.

b) (12 + 3² × 2) ÷ 10.

(12 + 9 × 2) ÷ 10.

30 ÷ 10 = 3.

c) [(3² - 2³) × 6² - (4² + V121)] × 2.

[(9 - 8) × 36 - (16 + 11)] × 2.

[1 × 36 - 27] × 2.

9 × 2 = 18.

d) 1 + {[2 + V256 × 10² ÷ (3 - 15⁰)] × 4}.

1 + {[2 + 16 × 100 ÷ (3 - 1)] × 4}.

1 + {[2 + 16 × 100 ÷ 2] × 4}.

1 + {802 × 4}.

1 + 3.208 = 3.209.