Question

a)-3/4+2/10-5/2-5/10=
b)7/3+2-1/3=
c)(1/3+1/2)-(5/6-3/4)=
d)1/2+(-0,3)+1/6=
e)0,4+3/5=
f)3-[-1/2-(0,1+1/4)]=
me ajudem pfv

Answer 1

$A) - \frac{3}{4}+ \frac{2}{10}- \frac{5}{2} - \frac{5}{10} = \\ - \frac{3}{4}+ \frac{1}{5}- \frac{5}{2} - \frac{1}{2} = \\ - \frac{-15+4-50-10}{20} = \\ - \frac{71}{20}$

$B) \frac{7}{3} +2- \frac{1}{3} = \\ \frac{7+6-1}{3} = \\ \frac{12}{3} = \\ 4$

$C) ( \frac{1}{3} + \frac{1}{2} ) - ( \frac{5}{6}- \frac{3}{4} ) = \\ \frac{5}{6} - \frac{1}{12}= \\ \frac{3}{4}$


$D) \frac{1}{2} + (-0,3)+ \frac{1}{6} = \\ \frac{1}{2} - 0,3 + \frac{1}{6} = \\ \frac{1}{2}- \frac{3}{10}+ \frac{1}{6}= \\ \frac{11}{30}$

$E) 0,4+ \frac{3}{5}= \\ \frac{2}{5} + \frac{3}{5} = \\ 1$

$F) 3-[- \frac{1}{2} -(0,1+ \frac{1}{4} )]= \\ 3-[- \frac{1}{2} - ( \frac{1}{10}+ \frac{1}{4} )]= \\ 3-[ - \frac{1}{2} - \frac{7}{20} ]= \\ 3-[- \frac{17}{20} ]= \\ 3+ \frac{17}{20} = \\ \frac{77}{20}$

Qualquer dúvida é só perguntar ;)