Question

a) {[(3/12 + 5/12)- 7/12]- 10/12 } =

b) {[(7/19 - 3/19 + 4/19)- 7/19] +5/19 =

c) {[( 5/13 - 6/13 + 8/13)+7/13 ]+ 5/13 - 2/13 } =

d) {[(1/10 + 8/10 - 2/10)-8/10 + 7/10]+ 2/10} =

me ajudem pfv
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Answer 1

Resposta:

Explicação passo a passo:

a) {[(3/12 + 5/12)- 7/12]- 10/12 } = {[8/12-7/12]-10/12} = {1/12-10/12}= -9/12

b) {[(7/19 - 3/19 + 4/19)- 7/19] +5/19 = {[8/19-7/19]+5/19}={1/19+5/19}= 6/19

c) {[( 5/13 - 6/13 + 8/13)+7/13 ]+ 5/13 - 2/13 } ={[7/13+7/13]+5/13}={14/13+5/13}=

 =19/13

d) {[(1/10 + 8/10 - 2/10)-8/10 + 7/10]+ 2/10} ={[7/10-1/10]+2/10}=(6/10+2/10}=8/10