Question

a) 3^0-3^-1+2^2=
b) 2^-2+(1/3)^2=
c) 5^0_(-1)-(1/2)^2=
​

Answer 1

Resposta:

$A)3^0-3^{-1}+2^2=\frac{14}{3}$

$B)2^{-2}+\left(\frac{1}{3}\right)^2=\frac{13}{36}$

$A)5^0-\left(-1\right)-\left(\frac{1}{2}\right)^2=\frac{7}{4}$

Explicação passo a passo:

$A)\\3^0-3^{-1}+2^2\\\\1-\frac{1}{3}+4\\\\5-\frac{1}{3}\\\\\frac{15}{3}-\frac{1}{3}\\\\\frac{15-1}{3}\\\\\frac{14}{3}$

$B)\\2^{-2}+\left(\frac{1}{3}\right)^2\\\\\frac{1}{4}+\frac{1}{9}\\\\\frac{9}{36}+\frac{4}{36}\\\\\frac{9+4}{36}\\\\\frac{13}{36}$

$C)\\5^0-\left(-1\right)-\left(\frac{1}{2}\right)^2\\\\5^0+1-\left(\frac{1}{2}\right)^2\\\\1+1-\frac{1}{4}\\\\2-\frac{1}{4}\\\\\frac{8}{4}-\frac{1}{4}\\\\\frac{8-1}{4}\\\\\frac{7}{4}$