Question

a) (2x²-9x+2)+(3x²+7x-1)= *
b) (5x²+5x-8)+(-2x²+3x-2)= *
c) (3x-6y+4)+(4x+2y-2)= *
d) (2x³+5x²+4x)+(2x³-3x²+x)= *
e) (5x²-2ax+a²)+(-3x²+2ax-a²)= *
2 segunda tarefa
a) (5x²-4x+7)-(3x²+7x-1)= *
b) (x²+2xy+y²)-(y²+x²+2xy)= *
d) (11ab+8c-7a)-(5c+4a-10ab)= *
e) (4x³+9x²+3x)-(7x³-6x²+8x)= *
3 tarefa
a) 2x.(x²-2x+5)= *
b) 4x.(3a+2b)= *
c) 7.( 8x-2y)= *
d) (2x+5).(2x-5)= *
e) (6x²-4).(6x²+4)=*
f) (3x+4).(2x-1)=*
me ajudem por favor​

Answer 1

Resposta:

a) (2x²-9x+2)+(3x²+7x-1)=

$2 {x}^{2} - 9x + 2 + 3 {x}^{2} + 7x - 1 \\ = 5 {x}^{2} - 2x + 1$

b) (5x²+5x-8)+(-2x²+3x-2)=

$5 {x}^{2} + 5x - 8 - 2 {x}^{2} + 3x - 2 \\ = 3 {x}^{2} + 8x - 10$

c) (3x-6y+4)+(4x+2y-2)=

$3x - 6y + 4 + 4x + 2y - 2 \\ = 7x - 4y + 2$

d) (2x³+5x²+4x)+(2x³-3x²+x)=

$2 {x}^{3} + 5 {x}^{2} + 4x + 2 {x}^{3} - 3 {x}^{2} + x \\ = 4 {x}^{3} + 2 {x}^{2} + 5x$

e) (5x²-2ax+a²)+(-3x²+2ax-a²)=

$5 {x}^{2} - 2ax + {a}^{2} - 3 {x}^{2} + 2ax - {a}^{2} \\ = 2 {x}^{2}$

2 segunda tarefa

a) (5x²-4x+7)-(3x²+7x-1)=

$5 {x}^{2} - 4x + 7 - 3 {x}^{2} - 7x + 1 \\ = 2 {x}^{2} - 11x + 8$

b) (x²+2xy+y²)-(y²+x²+2xy)=

${x}^{2} + 2xy + {y}^{2} - {y}^{2} - {x}^{2} - 2xy \\ = 0$

d) (11ab+8c-7a)-(5c+4a-10ab)=

$11ab + 8c - 7a - 5c - 4a + 10ab \\ = 21ab + 3c - 11a$

e) (4x³+9x²+3x)-(7x³-6x²+8x)= 

$4 {x}^{3} + 9 {x}^{2} + 3x - 7 {x}^{3} + 6 {x}^{2} - 8x \\ = - 3 {x}^{3} + 15 {x}^{2} - 5x$

3 tarefa

a) 2x.(x²-2x+5)=

$2 {x}^{3} - 4 {x}^{2} + 10x$

b) 4x.(3a+2b)=

$12ax + 8bx$

c) 7.( 8x-2y)=

$56x - 14y$

d) (2x+5).(2x-5)= 

$4 {x}^{2} - 10x + 10x - 25 \\ 4 {x}^{2} - 25$

e) (6x²-4).(6x²+4)=

$36 {x}^{4} + 24 {x}^{2} - 24 {x}^{2} - 16 \\ 36 {x}^{4} - 16$

f) (3x+4).(2x-1)=

$6 {x}^{2} - 3x + 8x - 4 \\ 6 {x}^{2} + 5x - 4$