Question

a ) 2x²+8x-8=0

b) 3x²7x+2=0​

Answer 1

Resposta:

2x² - 8x + 8

Δ = (-8)² - 4 (2)(8)

Δ = 64 - 64 = 0

x = -(-8) +- √Δ

       2(2)

x = 8 +- 0

        4

x¹ = 8 + 0 = 8 = 2

        4        4

x² = 8 + 0 = 8 = 2

        4        4

Resposta : 2

3x²-7x+2=0

a= 3   b= -7   c=+2

▲= b² -4.a.c= (-7)² -4.(3)(+2)= +49 -24=25

x= (-b±√▲)/2.a

x=(-(-7) ± √25)/2.3

x=(+7 ± 5)/6

x'=(7+5)/6= 12/6= 2

x"=(7-5)/6= 2/6 simplificando 2 e 6 por 2= 1/3

S= 2 e 1/3