Question

a) 2x²+3x+10=0 b) 2x²+3x+10=0​

Answer 1

$2x {}^{2} + 3x + 10 = 0 \\ \boxed{a = 2 \: , \: b = 3 \: , \: c = 10} \\ x = \frac{ - b± \sqrt{b {}^{2} - 4ac } }{2a} \\ x = \frac{ - 3± \sqrt{3 {}^{2} - 4 \: . \: 2 \: . \: 10} }{2 \: . \: 2} \\ x = \frac{ - 3± \sqrt{9 - 80} }{4} \\ x = \frac{ - 3± \sqrt{ - 71} }{4} \\ \boxed{\boxed{\boxed{x∉ℝ}}}$

att. yrz