Question

(a) 2x² – 2x – 4 = 0​

Answer 1

$\Box \ \ \boxed{\begin{array}{l}\sf 2x^2-2x-4=0 \end{array}}\\\\\\a = 2\\b=-2\\c=-4\\\\\\\Delta=b^2-4.a.c\\\Delta=(-2)^2-4.2.-4\\\Delta=4+32\\\Delta=36\\\\\\x=\dfrac{2\pm\sqrt{\Delta}}{2.2} \\\\\\x=\dfrac{2\pm6}{4}$

$x'=\dfrac{2+6}{4} \ \ \ x'=\dfrac{8}{4} \ \ \ \ \ \ x'=2\\\\\\x''=\dfrac{2-6}{4} \ \ \ x''=\dfrac{4}{4} \ \ \ \ \ \ x''=1$

$S=\{1 \ , 2 \}$

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