Matemática, perguntado por marlomebruno2, 6 meses atrás

a) 2x – 4(x – 12) = 4 b) 5 ( 1 – x) – 2x + 1 = - 3( 2 + x) c) 37 – 3( 2x + 1) = 4x - 6
b) 5 – 3( x + 2) = x – 29 e) 4( x + 10) – 2( x – 5) = 0 f) 15 +3 (x + 2) = - 7x + 2( x + 1)

c) 13 + 4( 2x – 1) = 5( x + 2) d) 5x - 2(3x + 2) = 1 – 2( 4x + 3)

Soluções para a tarefa

Respondido por bnineh05
0

Resposta:

a) 4

b) 3

c) 4

d) 7

e) - 25

f) - 2,375

g) \frac{1}{3}

h) \frac{-1}{7}

Explicação passo a passo:

a) 2x – 4(x – 12) = 4

2x - 4x + 12 = 4

2x - 4x = 4 - 12

-2x = -8                         (-1)

2x = 8

x = \frac{8}{2\\}

x = 4

b) 5(1 - x) - 2x + 1 = -3(2 + x)

5 - 5x - 2x + 1 = -6 -3x

-5x - 2x + 3x = -6 - 5 - 1             (-1)

5x + 2x - 3x = 6 + 5 + 1

4x = 12

x = \frac{12}{4\\}

x = 3  

c) 37 - 3(2x + 1) = 4x - 6

37 - 6x - 3 = 4x - 6

- 6x - 4x = -6 - 37 +3            (-1)

6x + 4x = 6 +37 - 3

10x = 40

x = \frac{40}{10}

x = \frac{4}{1}

x = 4

d) 5 -3(x + 2) = x - 29

5 - 3x - 6 = x - 29

- 3x -x = -29 - 5 + 6               (-1)

3x + x = 29 + 5 - 6

4x = 28

x -= \frac{28}{4}

x = 7

e) 4(x +10) - 2(x -5) = 0

4x + 40 - 2x + 10 = 0

4x - 2x = - 40 - 10

2x = -50

x = \frac{-50}{2}

x = -25

f) 15 + 3(x + 2) = - 7x + 2(x + 1)

15 + 3x + 6 = - 7x +2x +2

3x +7x - 2x = 2 - 15 - 6

8x = - 19

x = \frac{-19}{8}

x = - 2,375

g) 13 +4(2x - 1) = 5(x +2)

13 + 8x - 4 = 5x + 10

8x - 5x = 10 - 13 + 4

3x = 1

x = \frac{1}{3}

h) 5x - 2(3x + 2) = 1 - 2(4x + 3)

5x - 6x - 4 = 1 - 8x - 6

5x - 6x + 8x = 1 - 6 +4

7x = -1

x = \frac{-1}{7}

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