Question

a)2x +3x +9 =8 (6 -x)
b)4 (x + 10) -2 (x -5) =0

Answer 1

$A)2x +3x +9 =8 (6 -x) \\ \\ 2x+3x+9= 48-8x\\ \\ 2x+3x+8x= 48 - 9 \\ \\ 13x= 39 \\ \\ x= \dfrac{39}{13}\qquad\to\qquad \boxed{x= 3}$


$B)4 (x + 10) -2 (x -5) =0 \\ \\ 4x+40-2x+10= 0 \\ \\ 4x-2x= 0-40-10 \\ \\ 2x= -50 \\ \\ x= \dfrac{-50}{2}\qquad\to\qquad \boxed{x= -25}$

Answer 2

A)5x+9=48-8
5x+8x=48-9
13x=39
X=39/13
x=3

B) 4x+40-2x+10=o
4x-2x=-40-10
2x=-50
x= -50/2
x= -25