Question

a) (-2a²-3a+6)-(-4a²-5a+6)=

b) (4x³ - 6x² + 3x)-(7x³-6x² + 8x ) =

c) (x² + 2xy + y²) - (y² + x² + 2xy ) =

d) (x²+5x+3)-(4x²+6)=

e) (7ab +4c-3a)-(5c+ 4a-10) =

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Answer 1

Resposta:

a) (-2a²-3a+6)-(-4a²-5a+6)=

$- 2 {a}^{2} - 3a + 6 + 4 {a}^{2} + 5a - 6 \\ 2 {a}^{2} + 2a$

b) (4x³ - 6x² + 3x)-(7x³-6x² + 8x )

$4 {x}^{3} - 6 {x}^{2} + 3x - 7 {x}^{3} + 6 {x}^{2} - 8x \\ - 3 {x}^{3} - 5x$

c) (x² + 2xy + y²) - (y² + x² + 2xy )

${x}^{2} + 2xy + {y}^{2} - {y}^{2} - {x}^{2} - 2xy \\ = 0$

d) (x²+5x+3)-(4x²+6)

${x}^{2} + 5x + 3 - 4 {x}^{2} - 6 \\ - 3 {x}^{2} + 5x - 3$

e) (7ab +4c-3a)-(5c+ 4a-10)

$7ab + 4c - 3a - 5c - 4a + 10 \\ 7ab - c + 7a + 10$