a) (21+3)+(32+5)+(48+3)+1= 4
b) 4+2x8-3x5-1 =
c) 36+(5x4-3x6)x2-2x4=12
d) 107-{27+(36-2x5)-[2+3x(4-2)]-1}=
Soluções para a tarefa
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Resposta:
a) (21+3)+(32+5)+(48+3)+1=
24+37+51+1=
61+52=
113
b) 4+2x8-3x5-1
4+(16)-(15)-1=
4+1-1=
5-1=4
c)36+(5x4-3x6)x2-2x4=
36+(20-18)x2-2x4=
36+2x2-2x4=
36+4-8=
40-8=
32
d)107-{27+(36-2x5)-[2+3x(4-2)]-1}=
107-{27+(26)-[2+3x2]-1}=
107-{27+26-[8]-1}=
107-{44}=
63
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