Question

A(2,2) B (-4 -6) c (4-12) qual a distância percorrida

Answer 1

Vamos là.

AB² = (Ax - Bx)² + (Ay - By)²

AB² = (2 + 4)² + (2 + 6)² = 36 + 64 = 100

AB = 10

BC² = (Bx - Cx)² + (By - Cy)²

BC² = (-4 - 4)² + (-6 + 12)² = 64 + 36 = 100

BC = 10

AC² = (Ax - Cx)² + (Ay - Cy)²

AC² = (2 - 4)² + (2 + 12)² = 4 + 196 = 200

AC = 10√2

a distância percorrida

d = AB + BC + AC

d = 10 + 10 + 10√2

d = 10*(2 + √2)