Question

A) 1 e 0

B) -1 e 1

C) 0 e -1

D) 1 e -1

E) 0 e 2

Answer 1

$f(x) = 2 \\ {x}^{2} + x + 2 = 2 \\ {x}^{2} + x + 2 - 2 = 0 \\ {x}^{2} + x = 0 \\ x(x + 1) = 0 \\ x = 0 \: ou \: x + 1 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 1$


Alternativa c).