Question

a)(1/9)^2

b) 1/27 1/3

c) 2/1/9
Me ajudem a resolver pf!

Answer 1

$a) \\ {( \frac{1}{9}) }^{2} \\ \frac{ {1}^{2} }{ {9}^{2} } \\ \frac{1}{81}$

$b) \\ \frac{1}{27} \frac{1}{3} \\ \frac{1}{27} \times \frac{1}{3} \\ \frac{1 \times 1}{27 \times 3} \\ \frac{1}{81}$

$c) \\ \frac{2}{ \frac{1}{9} } \\ \frac{ \frac{2}{1} }{ \frac{1}{9} } \\ \frac{2 \times 9}{1 \times 1} \\ \frac{18}{1} \\ 18$