Question

a + 1 = 8 b) x + (2X-5)/3 = (3X+9)/3 ????

Answer 1

Explicação passo-a-passo:

a) $\sf a+1=8$

$\sf a=8-1$

$\sf a=7$

b) $\sf x+\dfrac{2x-5}{3}=\dfrac{3x+9}{3}$

$\sf 3x+2x-5=3x+9$

$\sf 5x-5=3x+9$

$\sf 5x-3x=9+5$

$\sf 2x=14$

$\sf x=\dfrac{14}{2}$

$\sf x=7$

Answer 2

Oie, Td Bom?!

a)

$a + 1 = 8$

$a = 8 - 1$

$a = 7$

b)

$x + \frac{2x - 5}{3} = \frac{ 3x + 9}{3}$

$3(x + \frac{2x - 5}{3} ) = 3 \: . \: \frac{3x + 9}{3}$

$3x + 3 \: . \: \frac{2x - 5}{3} = 3x + 9$

$3x + 2x - 5 = 3x + 9$

$2x - 5 = 9$

$2x = 9 + 5$

$2x = 14$

$x = \frac{14}{2}$

$x = 7$

Att. Makaveli1996