Question

A=(-1+(3/2-5))+8 e B=(-2(5-4/5)+3)

Answer 1

Olá, tudo bem?
Primeiro vamos calcular o valor de A e de B separadamente para depois fazer as operações pedidas:

$A=\left(-1+\left(\frac{2}{3}-5\right)\right)+8\\\\ A=\left(-1+\left(\frac{2-(5\cdot3)}{3}\right)\right)+8\\\\ A=\left(-1+\left( \frac{2-15}{3}\right)\right)+8\\\\ [tex]A=\left(-1+\left(\frac{-13}{3}\right)\right)+8\\\\ A= \frac{(-1\cdot3)-13}{3}+8\\\\ A= \frac{-3-13}{3}+8\\\\A= \frac{-16+(8\cdot3)}{3} A= \frac{-16+24}{3}\\\\ \boxed{A= \frac{8}{3}}$


$B=\left (-2\left(5-\frac{4}{5}\right)+3 \right )\\\\ B=\left (-2\left( \frac{(5\cdot5)-4}{5} \right)+3\right)\\\\ B=\left(-2\left(\frac{25-4}{5}\right)+3\right)\\\\ B=\left(\left(-2\cdot \frac{21}{5}\right) +3\right)\\\\ B=\left( \frac{-2\cdot21}{5}\right)+3\\\\ B= \frac{-42}{5}+3\\\\ B= \frac{-42+(3\cdot5)}{5}\\\\ B= \frac{-42+15}{5} \\\\ \boxed{B= \frac{-27}{5} }$

Agora respondemos as perguntas:

$A)A-B\\\\ \frac{8}{3}- \frac{-27}{5} \\\\ \frac{40-(-81)}{15}\\\\ \frac{40+81}{15}\\\\ \boxed{\boxed{A-B= \frac{121}{15} }}\\\\\\\\ B)A+5B\\\\ \frac{8}{3}+\left(5\cdot \frac{-27}{5}\right)\\\\ \frac{8}{3}+ \frac{5\cdot(-27)}{5}\\\\ \frac{8}{3}+ (-27)\\\\ \frac{8+(-27\cdot3)}{3}\\\\ \frac{8-81}{3}\\\\ \boxed{\boxed{A+5B= -\frac{73}{3} }}$