Question

a) 1/2-(-1)^4-(-1)^3=
b) (8y^4×^3)^2.(×^2y^3)^5=
c) (5.8)^4.(5^2.8^2)^4=
d) 12^-5/15^-3=​

Answer 1

Resposta:

Explicação passo a passo:

A)

$\frac{1}{2}-\left(-1\right)^4-\left(-1\right)^3\\\\\frac{1}{2}-1-\left(-1\right)^3\\\\\frac{1}{2}-1-\left(-1\right)\\\\\frac{1}{2}$

B

$\left(8y^4X^3\right)^2\left(X^2y^3\right)^5\\\\64y^8X^6\left(X^2y^3\right)^5\\\\64y^8X^6X^{10}y^{15}\\\\64y^{23}X^6X^{10}\\\\64y^{23}X^{16}$

C

$\left(5\cdot \:8\right)^4\left(5^2\cdot \:8^2\right)^4\\2560000\left(5^2\cdot \:8^2\right)^4\\2560000\cdot \:390625\cdot \left(8^2\right)^4\\2560000\cdot \:390625\cdot \:8^{2\cdot \:4}\\2560000\cdot \:390625\cdot \:8^8\\2560000\cdot \:390625\cdot \:16777216\\2560000\cdot \:6553600000000\\1.67772\dots E19$

D

$\frac{12^{-5}}{15^{-3}}\\\\\frac{3^{-5}\cdot \:4^{-5}}{15^{-3}}\\\\\frac{3^{-5}\cdot \:4^{-5}}{3^{-3}\cdot \:5^{-3}}\\\\\frac{4^{-5}}{3^2\cdot \:5^{-3}}\\\\\frac{125}{9216}$