Question

(9z^2-11)^2019x(9z^2-11)^-2018=0 qual valor de z?​

Answer 1

$\left(9z^2-11\right)^{2019}~.~\left(9z^2-11\right)^{-2018}~=~0\\\\\\\left(9z^2-11\right)^{2019\,+\,(-2018)}~=~0\\\\\\\left(9z^2-11\right)^{2019\,-\,2018}~=~0\\\\\\\left(9z^2-11\right)^{1}~=~0\\\\\\9z^2-11~=~0\\\\\\9z^2~=~11\\\\\\z^2~=~\dfrac{11}{9}\\\\\\z~=~\pm\sqrt{\dfrac{11}{9}}\\\\\\\boxed{z~=~\pm\dfrac{\sqrt{11}}{3}}$

Answer 2

Explicação passo-a-passo:

$(9z^{2} - 11 {)}^{2019} \times (9z^{2} - 11 {)}^{ - 2018} \\ (9z^{2} - 11 {)}^{2019 - 2018} \\ (9z^{2} - 11 {)}^{1} \\ 9z^{2} - 11$

• Espero ter ajudado.