Question

9x²-3x=0 com Bhaskara

Answer 1

9x²-3x=0
3x.(3x-1)=0
x.(3x-1)=0
x=0
3x-1=0
x=0
x=1/3

x1=0
x2=1/3

Answer 2

$9x^2 - 3x = 0 \\ a=9, \,\, b=-3, \,\, c=0 \\ \\ \Delta = b^2 - 4*a*c \\ \Delta = (-3)^2 - 4*9*0 \\ \Delta = 9 - 0 = 9 \\ \\ x = \frac{-b\pm \sqrt{\Delta}}{2*a} \\ \\ x = \frac{-(-3)\pm \sqrt{9}}{2*9} = \frac{3\pm3}{9} \\ \\ x' = \frac{3+3}{9} = \frac{6}{9} \Leftrightarrow x'= \frac{1}{3} \\ \\ x'' = \frac{3-3}{9} = \frac{0}{9} \Leftrightarrow x''=0$