Question

9x-2 = √27 equações exponenciais
(x-2) é em cima do nove

Answer 1

$9^{x-2}= \sqrt{27} \\ 9^{x-2} = 27^{ \frac{1}{2} } \\ (3^{2})^{x-2}=3^{\frac{3}{2}} \\ 3^{2(x-2)}=3^{\frac{3}{2}}$
$2(x-2)= \frac{3}{2} \\ x-2= \frac{3}{4} \\ x= \frac{3+8}{4} \\ x= \frac{11}{4}$

Answer 2

$9^{x-2} = \sqrt{27}$

$3^{2(x-2)} = 27^{ \frac{1}{2} }$

$3^{2x-4} = 3^{3. \frac{1}{2} }$

$2x-4= \frac{3}{2}$

mmc=2

$\frac{4x-8=3}{2}$

$4x=3+8$

$4x=11$

$x= \frac{11}{4}$