Question

9- (EEAR 2019) Sejam, a,b e c números reais positivos, com b#1. Se logo a =1,42 e log, c =- a²b 0,16 o valor de logb é: ( ) 3 ( )4 ( ) 5 ( )6​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_b\:a = 1,42}$

$\mathsf{log_b\:c = -0,16}$

$\mathsf{log_b\left(\dfrac{a^2b}{c}\right) = 2\:log_b\:a + log_b\:b - log_b\:c}$

$\mathsf{log_b\left(\dfrac{a^2b}{c}\right) = 2(1,42) + 1 - (-0,16)}$

$\mathsf{log_b\left(\dfrac{a^2b}{c}\right) = 2,84 + 1 + 0,16}$

$\boxed{\boxed{\mathsf{log_b\left(\dfrac{a^2b}{c}\right) = 4}}}$