Question

9. A solução do sistema linear 



(0, 0)

(1/2, 1/4)

(5, 2)

(1/2, 1/5)

(5, 1/5)

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Answer 1

Resposta:

2x-5y = 0 × (-1)

6x-5y = 2

-2x+5y = 0

6x-5y = 2

4x+0 = 2

x=2/4 ÷2

x = 1/2

2x-5y = 0

2×1/2 - 5y = 0

2/2-5y = 0

1-5y = 0

-5y = -1 ×(-1)

5y = 1

y = 1/5