Question

-9 + [ 26 + ( -7 -6 ) ] x ( -4 + 8 )

Answer 1

$\boxed{\begin{array}{l}\sf Em~uma~express\tilde ao~num\acute erica~resolve-se:\\\tt \bigg\cdot1~\sf pot\hat enciac_{\!\!,}\tilde ao~e~radiciac_{\!\!,}\tilde ao~(na~ordem~que~vier)\\\tt\bigg\cdot 2~\sf multiplicac_{\!\!,}\tilde ao~e~divis\tilde ao~(na~ordem~que~vier)\\\tt\bigg\cdot 3~\sf adic_{\!\!,}\tilde ao~e~subtrac_{\!\!,}\tilde ao~(na~ordem~que~vier)\\\rm Al\acute em~disso~eliminamos:\\\rm \bigg\cdot 1~\bigg(\bigg)\\\rm\bigg\cdot 2~\bigg\{\bigg\}\\\bigg\cdot 3~\bigg[~~\bigg]\end{array}}$

$\large\boxed{\begin{array}{l}\sf-9+[26+(-7-6)]\times(-4+8)\\\sf Vamos~eliminar~1^o~par\hat enteses:\\\sf -9+[26-13]\times4\\\sf Vamos~eliminar~o~colchete:\\\sf-9+13\times4\\\sf Agora~resolvemos~a~multiplicac_{\!\!,}\tilde ao:\\\sf-9+52=43\\\sf portanto\\\sf-9+[26-13]\times4=43\end{array}}$