Question

9-²-3-⁴ , pfv me ajuda

Answer 1

f) 0

${9}^{ - 2} - {3}^{ - 4} = \frac{1}{ {9}^{2} } - \frac{1}{ {3}^{4} } =$

$\frac{1}{9 \times 9} - \frac{1}{3 \times 3 \times 3 \times 3} = \frac{1}{81} - \frac{1}{81} = \frac{1 - 1}{81} =$

$\frac{0}{81} = 0$