Question

(9/16)^x-3 = (12/9)^x
Alguém detalha isso pra mim pff?

Answer 1

Boa noite 

(9/16)^(x - 3) = (12/9)^x 

vamos reescrever assim 

(3/4)^(2x - 6) = (4/3)^x 
(3/4)^(2x - 6) = (3/4)^-x 

bases iguais 

2x - 6 = -x
3x = 6

x = 2 

Answer 2

[(3^2/4^2)]^x-3= (12/9)^x

[(3/4)^2]^x-3= (4/3)^x

(3/4)^2x-6= (3/4)^-x

2x-6= -x

2x+x= 6

3x= 6
x= 6/3= 2