Question

{[(8x4+3)÷7+(3+15÷5)x3]x2+(19-7)}x2+12=

Answer 1

{[(8x4+3)÷7+(3+15÷5)x3]x2+(19-7)}x2+12=

{[(32+3)÷7+(3+3)x3]x2+12}x2+12=

{[35÷7+6x3]x2+12}x2+12=

{[5+18]x2+12}x2+12=

{23x2+12}x2+12=

{46+12}x2+12=

{58}x2+12=

116+12=

128