Question

8x²+7x-1=0 me ajude ​

Answer 1

$\LARGE\displaystyle{} {8x}^{2} + 7x - 1 = 0 \\\\ \LARGE\displaystyle{}\begin{cases}a = 8 \\ b = 7 \\ c = - 1\end{cases} \\\\ \LARGE\displaystyle{} \Delta = {7}^{2} - 4 \times 8 \times \left( - 1\right) \\ \LARGE\displaystyle{}\Delta = 49 - 4 \times 8 \times \left( - 1\right) \\ \LARGE\displaystyle{}\Delta = 49 + 32 \\ \LARGE\displaystyle{}\Delta = 81$

Então concluímos que: Possui duas soluções distintas.

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}} \blue{\:Estudos}}}}\end{gathered} }$