Question

8x²+2x-1=0 formula de Bhaskara

Answer 1

Δ=2²-4·8·(-1)

Δ= 4+32

Δ=36

x¹= 2+√36/2.8 ⇒ 2+6/16 ⇒ 8/16 = 1/2

x²= 2-√36/2.8 ⇒ 2-6/16 ⇒ -4/16 = -1/4

Answer 2

a= 8  b= 2  c= -1

Δ= b²-4.a.c

Δ= 2²-4.8.(-1)

Δ= 4+32

Δ= 36

x= [-b+-√Δ]/2.a

x= [-2+-√36]/2.8

x= [-2+-6]/16

x¹= [-2-6]/16 ⇒ x¹= -8/16 ⇒ x¹= -1/2

x²= [-2+6]/16 ⇒ x²= 4/16 ⇒  x²= 1/4

Resposta → S= {-1/2, 1/4}