Question

8x2-15=0 fórmula de bhaskara

Answer 1

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf 8x^2-15=0$

$\sf x=\dfrac{0\pm\sqrt{0^2-4\times8(-15)} }{2\times8}$

$\sf x=\dfrac{0\pm\sqrt{-4\times8(-15)} }{2\times8}$

$\sf x=\dfrac{0\pm\sqrt{-32(-15)} }{2\times8}$

$\sf x=\dfrac{0\pm\sqrt{480} }{2\times8}$

$\sf x=\dfrac{0\pm4\sqrt{30} }{2\times8}$

$\sf x=\dfrac{0\pm4\sqrt{30} }{16}$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=\dfrac{\sqrt{30} }{4}\approx1,369306394} }}}\ \checkmark$←← RESPOSTA.

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=-\dfrac{\sqrt{30} }{4}\approx-1,369306394} }}}\ \checkmark$←← RESPOSTA.

Explicação passo-a-passo:

ESPERO TER AJUDADO