Question

8x ao quadrado -7=0
quanto e

Answer 1

8x^2-7=0
delta=b^2-4.a.c
delta=0-4×8×(-7)
delta=224

224/2
112/2
56/2
28/2
14/2
7/7
0

x'=(-b+raiz de delta)/2.a
x'=(0+4.raiz(14))/16
x'=raiz(14)/4

x"=(-b-raiz de delta)/2.a
x"=(0-4.raiz(14))/16
x"=-raiz(14)/4