Question

8x ao quadrado -14×+3=0 como resolver?

Answer 1

8x²-14x+3=0
ax²+bx+c=0
a=8 b=-14 c=3

∆=b²-4ac
∆=(-14)²-4*8*3
∆=196-96
∆=100

x1=-b+√∆ / 2*a
x1=-(-14)+√100 / 2*8
x1=14+10 / 16
x1=26/16
x1=3/2


x2=-b-√∆ / 2a
x2=-(-14)-√100 / 2*8
x2=14-10 / 16
x2=4/16
x2=1/4