Question

[8B + B , QUANDO B = ] \frac{1}{2} [/tex]
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Answer 1

✅ Após resolver os cálculos, concluímos que o resultado da expressão algébrica é:

              $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf \frac{9}{2}\:\:\:}}\end{gathered} }$

Seja a expressão algébrica:

              $\Large\displaystyle\begin{gathered} 8B + B\end{gathered}$

Se:

                $\Large\displaystyle\begin{gathered} B = \frac{1}{2}\end{gathered}$

Então, temos:

      $\Large\displaystyle\begin{gathered} 8B + B = 8\cdot\frac{1}{2} + \frac{1}{2}\end{gathered}$

                        $\Large\displaystyle\begin{gathered} = \frac{8}{2} + \frac{1}{2}\end{gathered}$

                        $\Large\displaystyle\begin{gathered} = \frac{8 + 1}{2}\end{gathered}$

                        $\Large\displaystyle\begin{gathered} = \frac{9}{2}\end{gathered}$

✅ Portanto, o resultado da expressão algébrica é:

                         $\Large\displaystyle\begin{gathered} \frac{9}{2}\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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Answer 2

Resposta:

9/2

Explicação passo-a-passo:

8B+B, quando B=1/2

8•1/2+1/2=8/2+1/2=4+1/2 mmc=2

(8+1)/2==9/2