Question

86.sendo:
A=x-3
B=x-2
C=x+1
D=x+4
Caucule:
A)AB+C
B)A+CD
C)BD+C
D)ABC

Answer 1

Resolvendo :
A.-) AB + C
=> (x-3) (x-2) + (x+1)
=> x^2 - 2x - 3x + 6 + x + 1
=> x^2 - 5x + 6 + x + 1
=> x^2 - 4x +7

B.-) A + CD
=> x - 3 + ( x + 1 ) ( x + 4 )
=> x - 3 + x^2 + 4x + x + 4
=> x - 3 + x^2 + 5x + 4
=> x^2 + 6x + 1

C.-) BD + C
=> (x-2) (x+4) + ( x + 1 )
=> x^2 + x - 2x - 8 + x + 1
=> x^2 - x + x - 7
=> x^2 - 7

D.-) ABC
=> (x-3) (x-2) (x+1)
=> x^2 - 2x - 3x - 6 (x+1)
=> x^2 - 5x - 6 (x+1)
=> x^3 - 5x^2 - 6x - + x^2 - 5x - 6
=> x^3 - 4x^2 - 11x - 6