Question

8/x-5 + 1/x-1 = 3 equação de segundo grau​

Answer 1

$\mathsf{\dfrac{8}{x-5}+\dfrac{1}{x-1}=3\times(x-5)(x-1)}\\\mathsf{8(x-1)+1(x-5)=3(x^2-6x+5)}$

$\mathsf{3x^2-18x+15=8x-8+x-5}\\\mathsf{3x^2-18x-8x-x+15+8+5=0}\\\mathsf{3x^2-27x+28=0}$

$\mathsf{\Delta=729-336=393}\\\mathsf{x=\dfrac{27\pm\sqrt{393}}{6}\begin{cases}x_{1}=\dfrac{27+\sqrt{393}}{6}\\x_{2}=\dfrac{27-\sqrt{393}}{6}\end{cases}}$