Question

- 8. Seja a função quadrática f(x) = 8x2 – 3x - 5, calcule f(0), f(-2), f(1) e f(3). =​

Answer 1

Resposta:

$f(0)=-5\\\\f(-2)=33\\\\f(1)=0\\\\f(3)=58$

Explicação passo a passo:

$8)\ 8x^2-3x-5\\\\f(0)=8(0)^2-3(0)-5=8(0)-0-5=0-0-5=-5\\\\f(-2)=8(-2)^2-3(-2)-5=8(4)+6-5=32+6-5=33\\\\f(1)=8(1)^2-3(1)-5=8(1)-3-5=8-3-5=0\\\\f(3)=8(3)^2-3(3)-5=8(9)-9-5=72-9-5=58$