Question

8) QUESTÃO. O raio da base de um pirâmide reto mede 60 cm e a altura 25 cm. O apótema da pirâmide mede:
a) 13
b) 65
c) 100
d) 156
e) 1024​

Answer 1

Resposta:

b) 65

Explicação passo a passo:

Aplica-se Teorema Pitágoras nesse caso:

a² + b² = c²

O "c" valerá o apótema da pirâmide

25² + 60² = c²

625 + 3600 = c²

4225 = c²

c = 65

Answer 2

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⠀⠀⠀☞ O apótema desta pirâmide mede 65 [u.c.] (opção b). ✅

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⠀⠀⠀⭐⠀Para realizar este exercício utilizaremos o Teorema de Pitágoras.⠀⭐⠀

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⠀⠀⠀➡️⠀Sendo o raio o segmento de reta que liga o centro da base com a base do apótema (independente se temos um cone ou uma pirâmide regular) então temos daí um triângulo retângulo que nos permite usar a seguinte relação:

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$\LARGE\blue{\sf 60^2 + 25^2 = a^2}$

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$\LARGE\blue{\sf 3.600 + 625 = a^2}$

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$\LARGE\blue{\sf 4.225 = a^2}$

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$\LARGE\blue{\sf \sqrt{a^2} = \pm \sqrt{4.225}}$

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$\LARGE\blue{\sf \sqrt{a^2} = \pm 65}$

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⠀⠀⠀⭐ Como estamos interessados num comprimento então assumiremos somente a solução positiva desta radiciação, o que nos leva à opção b). ✌

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                                              $\qquad\qquad\huge\green{\boxed{\rm~~~\red{b)}~~\blue{ 65 }~~~}}$ ✅

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                             $\bf\large\red{\underline{\quad\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}$☁

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⠀⠀☀️ L͎̙͖͉̥̳͖̭̟͊̀̏͒͑̓͊͗̋̈́ͅeia mais sobre pirâmides:

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                                     https://brainly.com.br/tarefa/38601649 ✈  

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                                     $\huge\blue{\text{\bf\quad Bons~estudos.}}$ ☕

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                                          $\quad\qquad(\orange{D\acute{u}vidas\ nos\ coment\acute{a}rios})$ ☄

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                             $\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad }\LaTeX}$✍

                                $\sf(\purple{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly}$ ☘☀❄☃☂☻)

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                                                          $\Huge\green{\text{ \underline{\red{\mathbb{S}}\blue{\mathfrak{oli}}~}~\underline{\red{\mathbb{D}}\blue{\mathfrak{eo}}~}~\underline{\red{\mathbb{G}}\blue{\mathfrak{loria}}~} }}$ ✞

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