Question

8)Dada função y=x2-4x+3, determine as raízes.

Answer 1

x={3; 1}

Explicação:

x²-4x+3

a=1; b=-4; c=3

Δ = b²-4×a×c

Δ = (-4)²-4×a×c

Δ = 16-4×1×3

Δ = 16-4×3

Δ = 16-12

Δ = 4

$x \: = \: \frac{ - b \frac{ + }{} \sqrt{Δ} }{2 \times a} \\ x = \frac{ - ( - 4) \frac{ + }{} \sqrt{4} }{2 \times 1}$

$x \: = \frac{4 \frac{ + }{}2 }{2}$

${x}^{1} \: = \: \frac{4 + 2}{2} = \frac{6}{2} = 3$

$x {}^{2} = \frac{4 - 2}{2} = \frac{2}{2} = 1$